Web31 dec. 2014 · You might want to go for this code to check the type: Object value = field.get (currObj); if (value instanceof HashMap) // ... or even Object value = field.get (currObj); if (value instanceof Map) // ... Interlude: New source code as of now Web2 aug. 2024 · how to write the code below in java 8 using streams to avoid nested loop : C c1 = null; String name = "name1" for (A a: listOfAObjects) { for (B b: a.getList ()) { for (C c: b.getPr ()) { if (c.getName ().equalsIgnoreCase (name)) { c1= c; break; } } } } java list java-8 java-stream nested-loops Share Improve this question Follow
Java 8 get all elements in list - lacaina.pakasak.com
Web11 dec. 2024 · Syntax : E get (int index) Where, E is the type of element maintained by this List container. Parameter : This method accepts a single parameter index of type integer … WebYou need to use flatMap() in order to flatten the elements of the child list into a single list, otherwise you'd get a list of streams. Note 1: you don't need to use sequential(), since using stream() on the list of contacts already returns a sequential stream. Note 2: if you want the final list to be sorted, then you should use sorted() on the ... shipping agents to ghana
Filter and return value from a Map in Java 8 - Stack Overflow
WebTo get both names and surnames in the same list, you could do this: List set = persons.stream () .flatMap (p -> Stream.of (p.getName (),p.getSurname ())) .collect (Collectors.toList ()); Share Follow answered Feb 3, 2024 at 16:02 Landei 53.9k 12 97 195 1 That's it, thanks!!! It works, but could you please answer, what does flatMap mean? Web1 okt. 2024 · List nums = List.of (1, 2, 2); Map counts = nums.stream ().collect (Collectors.groupingBy (Function.identity (), Collectors.counting ())); return counts.entrySet ().stream ().filter (val -> val.getValue ().equals (1L)).map (Entry::getKey).findFirst ().orElse (-1); I found this answer in this post. Share Improve this … Web10 dec. 2024 · Retrieve single object from list using java8 stream api. I have a list of Employee, and I want to retrieve only one Employee information with the specific name: public static Employee getAllEmployeeDetails (String employeeName) { … queens bakery blyth